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A train leaves Chicago....

I'll say October 8th. I wonder if one or the other will start post padding (more than normal) to try and throw the contest, or if thier actions will offset each other?
 
Gonz said:
I'll say October 8th. I wonder if one or the other will start post padding (more than normal) to try and throw the contest, or if thier actions will offset each other?
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More than normal? :sign: I don't post pad. Except for this post. And a few others in the lounge. And a couple in some other topics.
 
ill go with monday november 14th

dont ask. lol

oh and the 75 mph train would catch up at 7pm and pass by the 6th hour(8pm)

disclaimer . . . i make up my own math rules sometimes and i pretend i am john nash or something lol
 
TheyCallMeManix said:
ill go with monday november 14th

dont ask. lol

oh and the 75 mph train would catch up at 7pm and pass by the 6th hour(8pm)

disclaimer . . . i make up my own math rules sometimes and i pretend i am john nash or something lol
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Actually, to be more mathmatically correct, given the variables, at 8:00PM, the trains would be in exactly the same place, side-by-side...then, depending on your method of timing them, and whether said timepiece was calibrated and in sync with the atomic clock, in Denver, CO, train 2 would begin to pass train 1...so at 8:00:01PM (8 o'clock & 1/100th of a minute) the nose of train 2 would be a few millimeters ahead of the nose of train 1...that would of course depend on the calibration and accuracy of your measuring device...furthermore, we have no way to know exactly when train 2 will completely pass train 1 as we do not have enough information to go on, i.e., the length of each train...so, theoretically, given the lack of knowledge of length of each train, and the possibility they may be infinite, train 2 may never completely pass train 1, until the end of the universe as we know it...
 
Since some monkey already took my birthday I will guess the day before (September 24th) at 12:00 EST.
 
Since you didnt state "if they continue to post at the same rate", thats kinda an open ended question there....what if SamClemmons started to post more than the 0.9 he posts now and bumped it up to more than mrjinglesusa now posts. At that rate, mrjinglesusa would never catch up! :p :p


This was a trick question....right?? :sign:
 
It can be shown that Sammy’s posts are equivalent to setting S(x') = - v/c^2 x', so that one obtains Jim’s transformation posting equations with the speed of Dial Up vs DSL c' = dr'/dt'(r=ct) = c constant in all frames.


Adjusting this formula to account for the hereshortly factor which is sure to ramp up Sammy's post frequency, one must set S(x') = 0 leading to the affine coordinate transformation which can only end in a date of Oct 13.



Head really hurts bad now.......


edited for clarity
 
Ok, I'll guess Oct 14!

There has been an influx of noobs lately, and Sam has been working overtime keeping them all in check.
 
preembargo said:
It can be shown that Sammy’s posts are equivalent to setting S(x') = - v/c^2 x', so that one obtains Jim’s transformation posting equations with the speed of Dial Up vs DSL c' = dr'/dt'(r=ct) = c constant in all frames.


Adjusting this formula to account for the hereshortly factor which is sure to ramp up Sammy's post frequency, one must set S(x') = 0 leading to the affine coordinate transformation which can only end in a date of Oct 13.



Head really hurts bad now.......


edited for clarity
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Heh heh... try again...

:sign:
 
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