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Cipher (DONE)

robbiex0r said:
I struggled with this, for many of the same reasons as C&G did.. my guess is that the original alphabet is aligned with numbers.. and those numbers are multiplied by something and modded by another number..

e(x) = a(x) mod b

now.. figuring out the multiplier and the mod.. b might = 26 ?
Click to expand...


I am thinking a key word is being used, but it is a little tough to fiqure out do to the length of the message... if I knew for sure what the box looks like, it would be easier... Here is the assumption that I am making:

-0123456789
1
2
3

I just can't devote anymore time to it. I do actually have work to do! LOL

C&G...
 
vigenere? stealing my contest ideas? but the number patterns dont tell of a Vigenere cipher.. and it's likely unbreakable without finding out the key.
 
a 3x9 matrix almost works..

a b c d e f g h i
j k l m n o p q r
s t u v w x y z


i tried flipping it so that the nine spot was an empty space..
s t u v w x y z
r q p o n m l k j
a b c d e f g h i

but it's just not working
 
robbiex0r said:
a 3x9 matrix almost works..

a b c d e f g h i
j k l m n o p q r
s t u v w x y z


i tried flipping it so that the nine spot was an empty space..
s t u v w x y z
r q p o n m l k j
a b c d e f g h i

but it's just not working
Click to expand...


I am thinking that it is a BOTCHED monome-dinome cipher with key word. -er...or maybe not botched... The nine without a number preceding might be a null (or space) Like this:

- 0 1 2 3 4 5 6 7 8 9
1 C I G A R S B D E F
2 H J K L M N O P Q T
3 U V W X Y Z

This could be supported by the fact that 36, 37, 38, 39 are not used. But also note that the 5 is not used in the second part of the dinome... that could be a wrench...
Note: I have figured out that the Stradding Checkerboard is not used.

C&G... eating and fiquring
 
C&G . i think you're onto something. Unfortunately, I threw out all my computer security notes from last semester... but I'm at work anyway. now we just have to guess a plausible keyword...

but the 9, for space...would be 19.. not just 9. :angry:
 
robbiex0r said:
C&G . i think you're onto something. Unfortunately, I threw out all my computer security notes from last semester... but I'm at work anyway. now we just have to guess a plausible keyword...

but the 9, for space...would be 19.. not just 9. :angry:
Click to expand...

Well, you would think so... but if you didn't want to use another number...then it works. The only reason I suspect this, is because it seems all the dinomes are already broken out:

20-31-9-19-10-21-13-31-30-14-16-31-9-14-27-23-20-28-30-33-18-32

vice what I would do if I constructed this:

20319 19102 11331 30141 63191 42723 20283 03318 32000

In my way you would HAVE to use another number to show the code breaker where to insert a space. Actually, in real-life, most codes would not use a space...:
whenb roken outal lthew ordsk inda runto gether
Oh...and to clear up the confusion...my box would look like this: (I use the "*" character to act as a space holder.)

*0 1 2 3 4 5 6 7 8 9
1 C I G A R S B D E F
2 H J K L M N O P Q T
3 U V W X Y Z - - -
 
Besides the ROT13 I tried last night I also tried to see if I could make it work as Hex and I couldn't get that to work either.
 
I recently got a pm asking for a hint. I will offer a few. There are no spaces. I have all of the words jammed together. I am afraid that I have made this too difficult. The code I have used works something like this

-- 1 2 3 4 5 6 7 8 9 .......
88 a b c d e f g h i .......
89 b c d e f g h i j.......
90 c d e f g h i j k.......


If for example the first letter of the sample were to be an "A" its number would be 88. If the second letter were to be a "D" its number would be 90. So the letter that the number represents changes at an even interval. I was just trying to have a little fun. If this proves too difficult, I will try to come up with another contest.
 
switters said:
I recently got a pm asking for a hint. I will offer a few. There are no spaces. I have all of the words jammed together. I am afraid that I have made this too difficult. The code I have used works something like this

-- 1 2 3 4 5 6 7 8 9 .......
88 a b c d e f g h i .......
89 b c d e f g h i j.......
90 c d e f g h i j k.......


If for example the first letter of the sample were to be an "A" its number would be 88. If the second letter were to be a "D" its number would be 90. So the letter that the number represents changes at an even interval. I was just trying to have a little fun. If this proves too difficult, I will try to come up with another contest.
Click to expand...

Correct me if I am wrong, but you made this impossible. If you were creating a code or cipher, for it to be of any use it would have to be decipherable by another user with a key. In your example, you are talking about a coordinate system that changes at an even interval. The problem is, your internals are changing, but the coordinate is incomplete. You supply the “y-axis” coordinate, but there is no “x-axis” coordinate. Granted, you are talking about the 1st and 2nd letters in the string, but even with the key, as a user, I won’t know what they are… (other than the fact that they change.) To make your example above correct, you would have to use 881=A, 902=D.
I believe your cipher similar to the internals of a tabula recta or Vigenère cipher, but you use dinome in the cipher when you should use a trinome.

Of course, if I am completely off base, I am an idiot and I apologize. :laugh:

C&G...your friendly neighborhood cryptanalyst
 
Cards&Gars said:
switters said:
I recently got a pm asking for a hint. I will offer a few. There are no spaces. I have all of the words jammed together. I am afraid that I have made this too difficult. The code I have used works something like this

-- 1 2 3 4 5 6 7 8 9 .......
88 a b c d e f g h i .......
89 b c d e f g h i j.......
90 c d e f g h i j k.......


If for example the first letter of the sample were to be an "A" its number would be 88. If the second letter were to be a "D" its number would be 90. So the letter that the number represents changes at an even interval. I was just trying to have a little fun. If this proves too difficult, I will try to come up with another contest.
Click to expand...

Correct me if I am wrong, but you made this impossible. If you were creating a code or cipher, for it to be of any use it would have to be decipherable by another user with a key. In your example, you are talking about a coordinate system that changes at an even interval. The problem is, your internals are changing, but the coordinate is incomplete. You supply the “y-axis” coordinate, but there is no “x-axis” coordinate. Granted, you are talking about the 1st and 2nd letters in the string, but even with the key, as a user, I won’t know what they are… (other than the fact that they change.) To make your example above correct, you would have to use 881=A, 902=D.
I believe your cipher similar to the internals of a tabula recta or Vigenère cipher, but you use dinome in the cipher when you should use a trinome.

Of course, if I am completely off base, I am an idiot and I apologize. :laugh:

C&G...your friendly neighborhood cryptanalyst
Click to expand...

I didn't make it to where 881 = A. I made it where the first letter in the cypher would "A" if the number was 88. So if in my code I wanted the message to be ( ABCDEFG ) It would read 88-88-88-88-88-88-88 or if the message were to be ( ADDD ) It would read 88-90-89-88 . Of course this is just for example.
 
switters said:
Cards&Gars said:
switters said:
I recently got a pm asking for a hint. I will offer a few. There are no spaces. I have all of the words jammed together. I am afraid that I have made this too difficult. The code I have used works something like this

-- 1 2 3 4 5 6 7 8 9 .......
88 a b c d e f g h i .......
89 b c d e f g h i j.......
90 c d e f g h i j k.......


If for example the first letter of the sample were to be an "A" its number would be 88. If the second letter were to be a "D" its number would be 90. So the letter that the number represents changes at an even interval. I was just trying to have a little fun. If this proves too difficult, I will try to come up with another contest.
Click to expand...

Correct me if I am wrong, but you made this impossible. If you were creating a code or cipher, for it to be of any use it would have to be decipherable by another user with a key. In your example, you are talking about a coordinate system that changes at an even interval. The problem is, your internals are changing, but the coordinate is incomplete. You supply the “y-axis” coordinate, but there is no “x-axis” coordinate. Granted, you are talking about the 1st and 2nd letters in the string, but even with the key, as a user, I won’t know what they are… (other than the fact that they change.) To make your example above correct, you would have to use 881=A, 902=D.
I believe your cipher similar to the internals of a tabula recta or Vigenère cipher, but you use dinome in the cipher when you should use a trinome.

Of course, if I am completely off base, I am an idiot and I apologize. :laugh:

C&G...your friendly neighborhood cryptanalyst
Click to expand...

I didn't make it to where 881 = A. I made it where the first letter in the cypher would "A" if the number was 88. So if in my code I wanted the message to be ( ABCDEFG ) It would read 88-88-88-88-88-88-88 or if the message were to be ( ADDD ) It would read 88-90-89-88 . Of course this is just for example.
Click to expand...

OK...Sports Fans, sorry to make your head hurt. But, this will be my last shot at understanding this.
Switters, if "88-88-88-88-88-88-88" would/could break out to "ABCDEFG", what would prevent it to breaking out to "GFEDCBA" or "DABCGFE"? I am sure you know how you encrypted it, but a guy on the other end would not know how to break it unless he had another coordinate, namely an "x-axis." You know how the rows are arranged, but without a knowing where to start in the column, anyone decrypting the message would not be able to, because they don't have a starting point.

Cheers!

C&G...
 
I've won several contests lately. So, time to bow out and let someone else win. I'm pretty reasonably sure I've got this figured out (Excel formulas + copy paste = win guys).

Hint-- notice the absence of a five.
 
jlada said:
I've won several contests lately. So, time to bow out and let someone else win. I'm pretty reasonably sure I've got this figured out (Excel formulas + copy paste = win guys).

Hint-- notice the absence of a five.
Click to expand...

Thats exactly how I made it. I'm sorry if this hasn't been a good contest. I was just messing around last night and thought this could be fun. I thought I had it set up in a manner that it could be cracked and jlada is definitely on the right track.
 
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