Here's a great idea...

[sonuvabum]

Here is a great way to save money on AA batteries.

The secret is out...

 

[Shooter]

MAYBE NOT

 

[Mrepp]

Interesting idea, until you find the one thats just battery acid.

 

[mmburtch]

Would the electrician in the crowd please explain how to hook 48 volts of batteries together to get 6 volts of output?

 

[Cparker]

I am not the electrician, but I am going to do some ciphering to guess.

32 batteries totaling 48 volts combined to form one battery of 6 volts. 32 batteries individually total 48 volts, but 8 batteries in a sequential circuit would still only produce 1.5 volts (I think, here may be the flaw in my logic).

So if I take the 32 batteries and make 4 columns of 8 batteries per column, then I get 1.5 volts per column for a cumulative output of 6 volts, not accounting for any energy lost in transmission, as each column would only be able to produce 1.5 volts, and the size of the column determine battery life.

Now I defer to the electrician.

Cparker

 

[tone-ny]

I am not the electrician, but I am going to do some ciphering to guess.

32 batteries totaling 48 volts combined to form one battery of 6 volts. 32 batteries individually total 48 volts, but 8 batteries in a sequential circuit would still only produce 1.5 volts (I think, here may be the flaw in my logic).

So if I take the 32 batteries and make 4 columns of 8 batteries per column, then I get 1.5 volts per column for a cumulative output of 6 volts, not accounting for any energy lost in transmission, as each column would only be able to produce 1.5 volts, and the size of the column determine battery life.

Now I defer to the electrician.

Cparker

That sounds about right, but I've been known to wrong :laugh:

 

[rbbrock]

I am not the electrician, but I am going to do some ciphering to guess.

32 batteries totaling 48 volts combined to form one battery of 6 volts. 32 batteries individually total 48 volts, but 8 batteries in a sequential circuit would still only produce 1.5 volts (I think, here may be the flaw in my logic).

So if I take the 32 batteries and make 4 columns of 8 batteries per column, then I get 1.5 volts per column for a cumulative output of 6 volts, not accounting for any energy lost in transmission, as each column would only be able to produce 1.5 volts, and the size of the column determine battery life.

Now I defer to the electrician.

Cparker

If I'm not mistaken, batteries in series (a column, end-to-end) combine their output (i.e. eight 1.5 v batteries in series = one 12 v battery), while batteries in parallel (a row, side-by-side) do not (i.e. eight 1.5 v batteries in parallel = one 1.5 v battery that lasts a long time). So you would need eight columns of four batteries, not four columns of eight.

 

[hoshnasi]

If I'm not mistaken, batteries in series (a column, end-to-end) combine their output (i.e. eight 1.5 v batteries in series = one 12 v battery), while batteries in parallel (a row, side-by-side) do not (i.e. eight 1.5 v batteries in parallel = one 1.5 v battery that lasts a long time). So you would need eight columns of four batteries, not four columns of eight.

I'm just a software engineer not an EE, but I believe this to be correct. Let me ask a cube mate.

Edit to say, "Yep" thats correct.

in the case a parallel circuit of 1.5 batteries. Each row will provide 1.5v. In a series though the 1.5v are added together.

 

[sonuvabum]

MAYBE NOT

Party pooper...



You gotta admit....they had fun with it though....

 

[Rebel Herfer]

I am not the electrician, but I am going to do some ciphering to guess.

32 batteries totaling 48 volts combined to form one battery of 6 volts. 32 batteries individually total 48 volts, but 8 batteries in a sequential circuit would still only produce 1.5 volts (I think, here may be the flaw in my logic).

So if I take the 32 batteries and make 4 columns of 8 batteries per column, then I get 1.5 volts per column for a cumulative output of 6 volts, not accounting for any energy lost in transmission, as each column would only be able to produce 1.5 volts, and the size of the column determine battery life.

Now I defer to the electrician.

Cparker

"220 ... 221, whatever works!" - ?anybody?

 

[Cparker]

Yep, 8 columns of four also makes sense for the size and shape of the battery.

Guess maybe I should call an electrician for the wiring job in the basement. ; )

Cparker

 

[Rebel Herfer]

I am not the electrician, but I am going to do some ciphering to guess.

32 batteries totaling 48 volts combined to form one battery of 6 volts. 32 batteries individually total 48 volts, but 8 batteries in a sequential circuit would still only produce 1.5 volts (I think, here may be the flaw in my logic).

So if I take the 32 batteries and make 4 columns of 8 batteries per column, then I get 1.5 volts per column for a cumulative output of 6 volts, not accounting for any energy lost in transmission, as each column would only be able to produce 1.5 volts, and the size of the column determine battery life.

Now I defer to the electrician.

Cparker

"220 ... 221, whatever works!" - ?anybody?

No takers? there's a 5er on it!

edited to add: mmnurtch is autoDQ

 

[bungpipe]

I am not the electrician, but I am going to do some ciphering to guess.

32 batteries totaling 48 volts combined to form one battery of 6 volts. 32 batteries individually total 48 volts, but 8 batteries in a sequential circuit would still only produce 1.5 volts (I think, here may be the flaw in my logic).

So if I take the 32 batteries and make 4 columns of 8 batteries per column, then I get 1.5 volts per column for a cumulative output of 6 volts, not accounting for any energy lost in transmission, as each column would only be able to produce 1.5 volts, and the size of the column determine battery life.

Now I defer to the electrician.

Cparker

"220 ... 221, whatever works!" - ?anybody?

No takers? there's a 5er on it!

edited to add: mmnurtch is autoDQ

Now is that a 5er of AA batteries? :whistling:

 

[JHolmes763]

"220 ... 221, whatever works!" - ?anybody?

No takers?

Only found it because of Google... I saw the movie, but can't remember the meaning behind it...

Michael Keaton in Mr. Mom (1983)

 

[Rebel Herfer]

I am not the electrician, but I am going to do some ciphering to guess.

32 batteries totaling 48 volts combined to form one battery of 6 volts. 32 batteries individually total 48 volts, but 8 batteries in a sequential circuit would still only produce 1.5 volts (I think, here may be the flaw in my logic).

So if I take the 32 batteries and make 4 columns of 8 batteries per column, then I get 1.5 volts per column for a cumulative output of 6 volts, not accounting for any energy lost in transmission, as each column would only be able to produce 1.5 volts, and the size of the column determine battery life.

Now I defer to the electrician.

Cparker

"220 ... 221, whatever works!" - ?anybody?

No takers? there's a 5er on it!

edited to add: mmnurtch is autoDQ

Now is that a 5er of AA batteries? :whistling:

Silly Noob :laugh: ... NO, but I like the way you think- you're dealing with RH! and you missed out to John. :sign: Better luck next time.

 

[Rebel Herfer]

We have a winner! Same FC, KY addy? PM me John - what your smokin', missin' or interested in so I have an idea what you might like.

FYI - He was doing some home improvements when his wife's boss came by the house and asked him if he was installing 220 electrical wiring. Classic movie scene, reminded me of my Dad at times.

"220 ... 221, whatever works!" - ?anybody?

No takers?

Only found it because of Google... I saw the movie, but can't remember the meaning behind it...

Michael Keaton in Mr. Mom (1983)

 

[Rebel Herfer]

"220 ... 221, whatever works!" - ?anybody?

No takers?

Only found it because of Google... I saw the movie, but can't remember the meaning behind it...

Michael Keaton in Mr. Mom (1983)

On its way - DC#0411 3097 9630 3606 5881

Thanks for Playin' :sign: honesty was appreciated. (Google)